16t^2+60t-1000=0

Solution for 16t^2+60t-1000=0 equation:

16t^2+60t-1000=0

a = 16; b = 60; c = -1000;
Δ = b2-4ac
Δ = 602-4·16·(-1000)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-260}{2*16}=\frac{-320}{32}
=-10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+260}{2*16}=\frac{200}{32}
=6+1/4
$